8q=(100+4q^2)/q

Solution for 8q=(100+4q^2)/q equation:

8q=(100+4q^2)/q

We move all terms to the left:

8q-((100+4q^2)/q)=0


Domain of the equation: q)!=0

q!=0/1

q!=0

q∈R


We multiply all the terms by the denominator


-((100+4q^2)+8q*q)=0


We calculate terms in parentheses: -((100+4q^2)+8q*q), so:

(100+4q^2)+8q*q

Wy multiply elements

(100+4q^2)+8q^2

We get rid of parentheses

4q^2+8q^2+100

We add all the numbers together, and all the variables

12q^2+100

Back to the equation:

-(12q^2+100)


We get rid of parentheses

-12q^2-100=0

a = -12; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·(-12)·(-100)
Δ = -4800
Delta is less than zero, so there is no solution for the equation